# 实现一个argsort

argsort?对数据进行排序，返回的不是排序后数据，而是排序数据的索引

python，借助enumerate对数据的遍历，得到元素的初始index

```python
X=[2,3,4,1,3,3,7]
>>> enumerate(X)
<enumerate object at 0x1069cd168>
>>> list(enumerate(X))
[(0, 2), (1, 3), (2, 4), (3, 1), (4, 3), (5, 3), (6, 7)]
>>> d=dict(enumerate(X))
{0: 2, 1: 3, 2: 4, 3: 1, 4: 3, 5: 3, 6: 7}
>>> d.items()
dict_items([(0, 2), (1, 3), (2, 4), (3, 1), (4, 3), (5, 3), (6, 7)])

# 按值排序items
>>> sorted(d.items(), key=lambda x: x[1])
[(3, 1), (0, 2), (1, 3), (4, 3), (5, 3), (2, 4), (6, 7)]
# 得到的可以就是排序索引
>>> list(r.keys())
[3, 0, 1, 4, 5, 2, 6]
```

```python
# argsort 实现
def argsort(X):
    d = dict(enumerate(X))
    r = dict(sorted(d.items(), key=lambda x: x[1]))
    return list(r.keys())


li = [2,3,4,1,3,3,7]
indies = argsort(li)
print(indies)

# [3, 0, 1, 4, 5, 2, 6]
```


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