# 54. 反转字符串中的单词 III

java

```java
/**
 * 557. 反转字符串中的单词 III
 *
 * 给定一个字符串，你需要反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初始顺序。
 *
 * 示例 1:
 *
 * 输入: "Let's take LeetCode contest"
 * 输出: "s'teL ekat edoCteeL tsetnoc"
 * 注意：在字符串中，每个单词由单个空格分隔，并且字符串中不会有任何额外的空格。
 */
public class Solution557 {
    public String reverseWords(String s) {
        String[] arr=s.split(" ");
        String str="";
        for(int i=0;i<arr.length;i++){
            str+=todo(arr[i])+" ";
        }
        return str.trim();
    }

    public String todo(String s) {
        String str="";
        for(int i=s.length()-1;i>=0;i--){
            str+=s.charAt(i);
        }
        return str;
    }

    public static void main(String[] args) {
        String s = "Let's take LeetCode contest";
        String r = new Solution557().reverseWords(s);
        System.out.println(r);
    }
}
```


---

# Agent Instructions: Querying This Documentation

If you need additional information that is not directly available in this page, you can query the documentation dynamically by asking a question.

Perform an HTTP GET request on the current page URL with the `ask` query parameter:

```
GET https://im-qianuxn.gitbook.io/pytorch/ji-suan-ji/shua-ti/zhi-shang-lei/54-fan-zhuan-zi-fu-chuang-zhong-de-dan-ci.md?ask=<question>
```

The question should be specific, self-contained, and written in natural language.
The response will contain a direct answer to the question and relevant excerpts and sources from the documentation.

Use this mechanism when the answer is not explicitly present in the current page, you need clarification or additional context, or you want to retrieve related documentation sections.